Basic Electrical Installation Work

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1.2A.4s.3.2. Example 2 A supply feeds domestic immersion heater wired 2.5(b) you can see that the time taken clear fault of 200A about 0. ∴ I t k S I t k 90 0 4 115 3 2 2 A s (from Table ) (mm (from Regul .5 mm2 CPC.3 when the protective device 30A semi-enclosed fuse.0 mm2 where mechanical protection not provided order comply with Regulation 544.10 mm2 found calculation.1.3).4s from Regulation 411. From Table 3.3. The CPC the cable greater than 0. The circuit correctly protected with 15A semi-enclosed fuse 3036. From Fig.4s.5mm2 PVC insulated copper cable and incorporates 1.1.49mm2 and therefore suitable. t Maximum operating time the protective device for circuit not exceeding 32A 0. So, this case the table states that 90A will trip 15A semi-enclosed fuse 0. I V Z Maximum fault current (A) A s ∴ 230 1 15 200 . For final circuits less than 32A the maximum operating time the protective device 0. .15Ω. .2A can seen that current about 90A will trip the 15A fuse 0. a ation 543. . k 115 (from Table 54. Verify that the 1. Establish calculation that the CPC adequate size meet the requirements Regulation 543. 12.5mm CPC meets the requirements Regulation 543. .2. The small insert Table the top right Table 3. The characteristics the protective device are given IEE Regulation Table 3.Overcurrent, short circuit and earth fault protection 251 as 1. A 1.4s.3.4s.2 the IEE Regulations gives the value the prospective fault current required operate the device within the various disconnection times given.2.3) ( s mm S 90 4 115 0 49 2 2 .5mm2 where mechanical protection provided or 4. S I t k S 2 2 2 2 200 4 115 1 10 (mm ) ( s mm .5 mm2 CPC acceptable since this the nearest standard-size conductor above the minimum cross-sectional area 1. the protective conductor separate conductor, that is, does not form part cable this example and not enclosed wiring system Example the cross-section the protective conductor must not less than 2