Basic Electrical Installation Work

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a result, the supply companies encourage installation engineers improve their power factor to value close and sometimes charge penalties the power factor falls below 0. There may also the problem higher voltage drops the supply cables.6 900 W φ ∴ The power factor most industrial loads lagging because the machines and discharge lighting used industry are mostly inductive. When this capacitor current added the load current shown Fig 10. This causes an additional magnetizing current drawn from the supply, which does not produce power, but does need supplied, making supply cables larger. POWER FACTOR CORRECTION Most installations have low bad power factor because the inductive nature the load.4: I 1840 230 4 20 W V A . the p. Figure 10. Calculate the current each power factor.8 and 0. It can seen from these calculations that 1.84 load supplied power factor 0. The current given by: I P V cos φ where 1.9(b) the resultant load current has much improved power factor. 10.Alternating current theory and electrical machines 203 For (d): P VI P cos (W) 150 0.4 would require 20A cable, while the same load unity power factor could supplied with an cable.9(c).4.8.f.8 10A For p.84kW loads with power factors 0. . then: I 1840 230 1 8 W V A For p.9(a) shows industrial load with low power factor. 0. capaci- tor connected parallel with the load, the capacitor current leads the applied voltage 90°.f.8: I 1840 230 W V 0. capacitor has the opposite effect inductor, and so seems reasonable add capacitor load which known have a lower bad power factor, for example, motor.f. 0. Example 3 A 230V supply feeds three 1.84 1840 and 230V. However, using slightly bigger capacitor, the load current can pushed until ‘in phase’ with the voltage can be seen Fig