Basic Electrical Installation Work

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8 and 0.6 900 W φ ∴ The power factor most industrial loads lagging because the machines and discharge lighting used industry are mostly inductive.4. Figure 10. capaci- tor connected parallel with the load, the capacitor current leads the applied voltage 90°. capacitor has the opposite effect inductor, and so seems reasonable add capacitor load which known have a lower bad power factor, for example, motor. However, using slightly bigger capacitor, the load current can pushed until ‘in phase’ with the voltage can be seen Fig. 0.8.Alternating current theory and electrical machines 203 For (d): P VI P cos (W) 150 0. The current given by: I P V cos φ where 1. then: I 1840 230 1 8 W V A For p. a result, the supply companies encourage installation engineers improve their power factor to value close and sometimes charge penalties the power factor falls below 0.f.9(b) the resultant load current has much improved power factor.4: I 1840 230 4 20 W V A .84 load supplied power factor 0. There may also the problem higher voltage drops the supply cables.f. . Example 3 A 230V supply feeds three 1. POWER FACTOR CORRECTION Most installations have low bad power factor because the inductive nature the load. When this capacitor current added the load current shown Fig 10.84kW loads with power factors 0. 10.8: I 1840 230 W V 0.f.9(c). the p. It can seen from these calculations that 1.84 1840 and 230V.8 10A For p. This causes an additional magnetizing current drawn from the supply, which does not produce power, but does need supplied, making supply cables larger.9(a) shows industrial load with low power factor. Calculate the current each power factor. 0.4 would require 20A cable, while the same load unity power factor could supplied with an cable